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Proof step 4 from proof short-div-ngr (previous step)

¬(0 < j ∧ s2i(sho) < 65536 ∧ 0 ≤ s2i(sho)), 65536 ≤ s2i(sho) / j, 0 < s2i(sho) / j, 0 ≤ s2i(sho) / j ⊦ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
65536 ≤ s2i(sho) / j, 0 < s2i(sho) / j, 0 ≤ s2i(sho) / j ⊦ j = 0, ¬ j < 0 ∧ ¬ s2i(sho) < 0

Rule argument

Additional information

Used simplifier rules: short-max: ⊦ ¬ 65536 ≤ s2i(sho);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ ¬ i < j ↔ j ≤ i;