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Proof step 2 from proof short-div256 (previous step)

0 < s2i(sho) / 256, 256 < s2i(sho) / 256 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 3:
0 < s2i(sho) / 256, 256 < s2i(sho) / 256 ⊦ s2i(sho) / 256 < 32768 / 256

Rule argument

fma: s2i(sho) / 256 < 32768 / 256

Additional information

Used simplifier rules: ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; Used formulas: s2i(sho) / 256 < 32768 / 256