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Proof step 7 from proof short-in (previous step)

0 ≤ i ∧ i % 65536 ≤ 32767, i ≤ 32767, 0 ≤ i ⊦ i % 65536 = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 ≤ i, i ≤ 32767, i % 65536 ≤ 32767 ⊦ i % 65536 = i

Rule argument

Additional information