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Proof step 1 from proof short-inj (conclusion)

⊦ i2s(i) = i2s(j) ↔ s2i(i2s(i)) = s2i(i2s(j))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ s2i(shoi) = s2i(shoj) ↔ shoi = shoj

Rule argument

name: short-equal rotate: F subst: [shoj, shoi] → [i2s(j), i2s(i)]

Additional information

Used terms: i2s(j), i2s(i)