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Proof step 1 from proof short-inrange (conclusion)

⊦ ~32768 ≤ i ∧ i < 32768 → s2i(i2s(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
~32768 ≤ i, i < 32768 ⊦ s2i(i2s(i)) = i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)