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Proof step 1 from proof short-larger (conclusion)

⊦ 32768 ≤ i → i2s(i) = i2s(i - 2 ^ 16)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
32768 ≤ i, 0 < i, 0 ≤ i ⊦ i2s(i) = i2s(i - 65536)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)