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Proof step 1 from proof short-law-ls-not (conclusion)

⊦ (i = 32767 ∧ j = 32768 → ¬(i < j → s2i(i2s(i)) < s2i(i2s(j)))) ∧ (i = 32768 ∧ j = 1 → ¬(s2i(i2s(i)) < s2i(i2s(j)) → i < j)) ∧ (i = 65535 ∧ j = ~1 → ¬(s2i(i2s(i)) = s2i(i2s(j)) → i = j))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: num-issi: ~32768 ≤ i, i ≤ 32767 ⊦ s2i(i2s((* i))) = i;%sis-pos-upper: ⊦ 32768 ≤ i ∧ i < 65536 → s2i(i2s(i)) = i - 65536;%sis-01: ⊦ s2i(i2s(1)) = 1;