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Proof step 14 from proof short-law-righthift-not (previous step)

⊦ ( i = 32768 ∧ j = 1 → i2s((# int2bits(32768) ≤ 1 ⊃ 0;bits2int(sublist(0, # int2bits(32768) - 1, int2bits(32768))))) ≠ i2s((# int2bits(~32768) ≤ 1 ⊃ ~1;bits2int(sublist(0, # int2bits(~32768) - 1, int2bits(~32768)))))) ∧ ( i = 32768 ∧ j = 1 → i2s(bits2int(sublist(0, # fillsgn(32, int2bits(32768)), false ' + fillsgn(32, int2bits(32768))))) ≠ i2s(bits2int(sublist(0, # fillsgn(32, int2bits(~32768)), false ' + fillsgn(32, int2bits(~32768))))))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: 0 ≤ i ⊦ int2bits((* i)) = uint2bits(i) subst: [i] → [32768] rotate: F spec: int2bits inst: name: int2bits-pos-num

Additional information

Used terms: 32768