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Proof step 8 from proof short-law-righthift-not (previous step)

⊦ ( i = 32768 ∧ j = 1 → i2s ((# int2bits(32768) ≤ i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) ⊃ 0 ;bits2int(sublist(0, # int2bits(32768) - i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), int2bits(32768))) )) ≠ i2s ((# int2bits(~32768) ≤ i→n(bits2int(bitsand(int2bits(1), int2bits(31)))) ⊃ ~1 ;bits2int(sublist(0, # int2bits(~32768) - i→n(bits2int(bitsand(int2bits(1), int2bits(31)))), int2bits(~32768))) ))) ∧ ( i = 32768 ∧ j = 1 → i2s (bits2int (sublist(0, # fillsgn(32, int2bits(32768)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(32768))))) ≠ i2s (bits2int (sublist (0, # fillsgn(32, int2bits(~32768)), mklist(false, i→n(bits2int(bitsand(int2bits(1), int2bits(31))))) + fillsgn(32, int2bits(~32768))))))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → int2bits(i) = uint2bits(i) subst: [i] → [1] rotate: F spec: int2bits inst: name: int2bits-pos

Additional information

Used terms: 1