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Proof step 3 from proof short-law-sub-one-01 (previous step)

⊦ s2i(i2s(j - j0)) = s2i(i2s(j - cast(16, j0)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ s2i(i2s(i)) = cast(16, i)
Proof step 5:
⊦ s2i(i2s(j - j0)) = cast(16, j - cast(16, j0))

Rule argument

name: short-is-cast rotate: F subst: [i] → [j - cast(16, j0)]

Additional information

Used terms: j - cast(16, j0)