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Proof step 5 from proof short-law-xor-one (previous step)

⊦ s2i(i2s(bxor(j, j0))) = cast(16, bxor(cast(16, j), j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ s2i(i2s(i)) = cast(16, i)
Proof step 7:
⊦ cast(16, bxor(j, j0)) = cast(16, bxor(cast(16, j), j0))

Rule argument

name: short-is-cast rotate: F subst: [i] → [bxor(j, j0)]

Additional information

Used terms: bxor(j, j0)