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Proof step 3 from proof short-max-11 (previous step)

⊦ i = 0, 65536 * i + s2i(sho) < 32768 ↔ ¬ 0 < i

User applied rule cut formula

And obtained the following new goals

Proof step 4:
i < 0 ⊦ i = 0, 65536 * i + s2i(sho) < 32768 ↔ ¬ 0 < i
Proof step 10:
⊦ i < 0, i = 0, 65536 * i + s2i(sho) < 32768 ↔ ¬ 0 < i

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0