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Proof step 5 from proof short-max-11 (previous step)

32768 ≤ 65536 * i + s2i(sho), i < 0, 0 < 65536 * i + s2i(sho), 0 ≤ 65536 * i + s2i(sho) ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: 0 < 65536 * i + 32768

Additional information

Used simplifier rules: ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ 0 < i ∧ j < 0 → ((* j) < (* i) * i0 ↔ (j + 1 - i) / i < i0);% ⊦ ~1 < i ↔ 0 ≤ i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i < j → ¬ j < i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used formulas: 0 < 65536 * i + 32768