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Proof step 1 from proof short-mod-01 (conclusion)
i ≠ 0 ⊦ s2i(i2s(s2i(sho) % i)) = s2i(sho) % i
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ i = 0, s2i(i2s(s2i(sho) % i)) = s2i(sho) % i
Rule argument
Additional information