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Proof step 4 from proof short-mod-ngr (previous step)

¬(0 < s2i(sho0) ∧ 0 ≤ s2i(sho) ∧ s2i(sho0) ≤ 65536), 65536 ≤ s2i(sho) % s2i(sho0), 0 < s2i(sho) % s2i(sho0), 0 ≤ s2i(sho) % s2i(sho0) ⊦ s2i(sho0) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: short-max-06: ⊦ 32767 ≤ i → ¬ i < s2i(sho);% ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < 0 ∧ j ≠ 0 → ¬ 0 < i % j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ ¬ i < j ↔ j ≤ i;