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Proof step 4 from proof short-mod (previous step)

65536 ≤ abs(s2i(sho)) ⊦ s2i(sho) % 65536 = s2i(sho), s2i(sho) = 0

User applied rule insert lemma

And obtained the following new goals

Rule argument

name: short-range subst: [sho] → [sho]

Additional information

Used terms: sho