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Proof step 3 from proof short-mult-65536 (previous step)

⊦ i2s(cast(16, i * 65536 + j)) = i2s(j)

User applied rule cut formula

And obtained the following new goals

Proof step 4:
65536 = 2 ^ 16 ⊦ i2s(cast(16, i * 65536 + j)) = i2s(j)

Rule argument

fma: 65536 = 2 ^ 16

Additional information

Used formulas: 65536 = 2 ^ 16