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Proof step 1 from proof short-shift-pos (conclusion)

⊦ 0 < s2i(sho) → s2i(i2s(s2i(sho) i>> 8)) = s2i(sho) i>> 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < s2i(sho) ⊦ s2i(i2s(s2i(sho) i>> 8)) = s2i(sho) i>> 8

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs