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Proof step 12 from proof short-size (previous step)

¬ s2i(sho) < ~1, 16 < # int2bits(s2i(sho)), s2i(sho) ≤ 0 ⊦ # int2bits(s2i(sho)) - 1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)% ⊦ ¬ i < j ↔ j ≤ i;