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Proof step 4 from proof short-size (previous step)

2 ^ 15 < 2 ^ n→i(# int2bits(s2i(sho)) - 1) ⊦ # int2bits(s2i(sho)) - 1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ 0 ≤ j → (2 ^ j < 2 ^ j0 ↔ j < j0)
Proof step 6:
0 ≤ 15, 15 < n→i(# int2bits(s2i(sho)) - 1) ⊦ # int2bits(s2i(sho)) - 1 = 0

Rule argument

seq: ⊦ 0 ≤ j → (2 ^ j < 2 ^ j0 ↔ j < j0) subst: [j0, j] → [n→i(# int2bits(s2i(sho)) - 1), 15] rotate: F spec: int-pot inst: name: ls-pos-2pot

Additional information

Used terms: n→i(# int2bits(s2i(sho)) - 1), 15