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Proof step 1 from proof sis-03 (conclusion)

⊦ i + j ≤ 32767 ∧ 0 ≤ i ∧ 0 ≤ j → s2i(i2s(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i + j ≤ 32767, 0 ≤ i, 0 ≤ j ⊦ s2i(i2s(i)) = i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)