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Proof step 5 from proof sis-03 (previous step)

0 ≤ j, 0 ≤ i, i + j ≤ 32767 ⊦ s2i(i2s(i)) = i, i ∈short

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i ∈short ↔ ~32768 ≤ i ∧ i ≤ 32767

Rule argument

name: inshort rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: short-max-10: ⊦ 32767 < i → s2i(sho) ≠ i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)%i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i + j < j ↔ i < 0;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: i