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Proof step 1 from proof sis-05 (conclusion)

⊦ 0 ≤ i ∧ i ≤ 10 → s2i(i2s(i * 141)) = i * 141

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ 10, 0 ≤ i ⊦ s2i(i2s(i * 141)) = i * 141

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)