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Proof step 6 from proof sis-ls-same (previous step)

i % 65536 < i, i < 0, i < i % 65536 + 65536, ~32768 ≤ i, i % 65536 < ~32768, ~98304 < i % 65536 ⊦ i % 65536 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ abs(i) < j → i % j = i

Rule argument

seq: ⊦ abs(i) < j → i % j = i subst: [j, i] → [65536, i] rotate: F spec: int-div inst: name: mod-zero-05

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;% ⊦ ~ i < j ↔ 0 < j + i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;%i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ¬ i < i; Used terms: 65536, i