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Proof step 1 from proof sis-neg-high (conclusion)

⊦ i < 0 ∧ ~32768 ≤ i % 65536 → s2i(i2s(i)) = i % 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
~32768 ≤ i % 65536, i < 0 ⊦ s2i(i2s(i)) = i % 65536

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)