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Proof step 17 from proof sis-neg-high (previous step)

i0 < 0 ⊦ i0 = 0, s2i(i2s(bits2int(lastn(16, int2bits(65536 * i0))))) = 0

User applied rule cut formula

And obtained the following new goals

Proof step 18:
65536 = 2 ^ 16, i0 < 0 ⊦ i0 = 0, s2i(i2s(bits2int(lastn(16, int2bits(65536 * i0))))) = 0

Rule argument

fma: 65536 = 2 ^ 16

Additional information

Used formulas: 65536 = 2 ^ 16