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Proof step 32 from proof sis-neg-high (previous step)

2 * i0 - 1 < 0 ∧ 2 * i0 - 1 ≠ ~1, i0 < 0 ⊦ i0 = 0, s2i(i2s(bits2int(lastn(16, (int2bits((2 * i0 - 1 - 1) / 2) + (~1 = (2 * i0 - 1) % 2)') + mklist(false, 15))))) = ~32768

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i < 1 ↔ i ≤ 0;% ⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 < (* j) ↔ i0 < (i + j - 1) / i);% ⊦ i - j < i0 ↔ i < j + i0;% ⊦ 2 * i = 0 ↔ i = 0;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ i < 0 → (2 * i - 1) % 2 = ~1;%j ≠ 0 ⊦ (i * j) / j = i;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j - i = i * (j - 1);% ⊦ i - j - i0 = i - j + i0;