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Proof step 4 from proof sis-neg-low (previous step)

¬(~32768 ≤ i ∧ i ≤ 32767), i < 0, i % 65536 < ~32768 ⊦ s2i(i2s(i)) = i % 65536 + 65536, i % 65536 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < 0, i % 65536 < ~32768, i < ~32768 ⊦ s2i(i2s(i)) = i % 65536 + 65536, i % 65536 = 0

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs