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Proof step 39 from proof sis-on-bits (previous step)

16 ≤ # int2bits(i) ⊦ s2i(i2s(bits2int(lastn(16, int2bits(i))))) = bits2int(lastn(16, int2bits(i))), i ∈short

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 40:
⊦ i ∈short ↔ ~32768 ≤ i ∧ i ≤ 32767
Proof step 41:
16 ≤ # int2bits(i) ⊦ s2i(i2s(bits2int(lastn(16, int2bits(i))))) = bits2int(lastn(16, int2bits(i))), ~32768 ≤ i ∧ i ≤ 32767

Rule argument

name: inshort rotate: F subst: [i] → [i]

Additional information

Used terms: i