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Proof step 20 from proof sis-pos-high (previous step)

# int2bits(j0) = 16 + 1, # int2bits(j0) = 17, j0 < 65536, 32767 < j0, 0 ≤ j0, 0 < j0 ⊦ j0 = s2i(i2s(bits2int(int2bits(j0).rest))) + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2