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Proof step 25 from proof sis-pos-high (
previous step
)
0 ≤ j0, 0 < j0, # int2bits(j0) = 17, j0 < 65536, 32767 < j0, 0 ≤ j0, 0 < j0 ⊦ j0 = s2i(i2s(j0 - 2 ^ (n→i(# int2bits(j0)) - 1))) + 65536
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 26
:
# int2bits(j0) = 17, 0 < j0, 0 ≤ j0, 32767 < j0, j0 < 65536 ⊦ j0 = s2i(i2s(j0 - 65536)) + 65536
Rule argument
Additional information