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Proof step 22 from proof sis-pos-low (previous step)

¬ # int2bits(j) ≤ 17, 32767 < 65536 * i0 + j, j ≤ 32767, 0 < 65536 * i0 + j, 0 ≤ j, 0 ≤ i0, 0 < i0 ⊦ s2i(i2s(bits2int(lastn(16, int2bits(i0) + fillsgn(17, int2bits(j)).rest)))) = j, fillsgn(17, int2bits(j)) = [], 16 = # fillsgn(17, int2bits(j)) - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;