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Proof step 1 from proof ubyte-div-lsz (conclusion)

⊦ ub2i(by) ≠ 0 → (i / ub2i(by) < 0 ↔ i + ub2i(by) ≤ 0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ ub2i(by) = 0, i / ub2i(by) < 0 ↔ ¬ 0 < i + ub2i(by)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;