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Proof step 11 from proof ubyte-inj (previous step)

b2i(by) < 0, 256 + b2i(by) = ub2i(by0) ⊦ by = by0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ b2i(by) < 0 → ub2i(by) = 256 + b2i(by)
Proof step 13:
¬ b2i(by0) < 0, b2i(by) < 0, 256 + b2i(by) = ub2i(by0) ⊦ by = by0

Rule argument

name: ubyte-neg rotate: F subst: [by] → [by0]

Additional information

Used simplifier rules: byte-equal: ⊦ b2i(byi) = b2i(byj) ↔ byi = byj;% ⊦ i + j = i + i0 ↔ j = i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: by0