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Proof step 7 from proof ubyte-inj (previous step)

b2i(by0) < 0, b2i(by) = 256 + b2i(by0), 0 ≤ 256 + b2i(by0) ⊦ by = by0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
b2i(by) = 256 + b2i(by0), ~256 ≤ b2i(by0), b2i(by0) < 0 ⊦ by = by0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;