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Proof step 2 from proof ubyte-max-02 (previous step)

0 < ub2i(by), 256 < ub2i(by) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ b2i(by) < 0 → ub2i(by) = 256 + b2i(by)

Rule argument

name: ubyte-neg rotate: F subst: [by] → [by]

Additional information

Used simplifier rules: ubyte-pos: ⊦ 0 ≤ b2i(by) → ub2i(by) = b2i(by);%byte-ngr: i ≥ 127 ⊦ ¬ (* i) < b2i(by);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i < j → ¬ j < i; Used terms: by