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Proof step 1 from proof ubyte-mod (conclusion)

⊦ ub2i(by) ≠ 0 → ¬ 256 ≤ i % ub2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
256 ≤ i % ub2i(by), 0 < i % ub2i(by), 0 ≤ i % ub2i(by) ⊦ ub2i(by) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)