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Proof step 1 from proof ubyte-mult (conclusion)

⊦ ¬ 65536 ≤ ub2i(by) * ub2i(by0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
65536 ≤ ub2i(by) * ub2i(by0), 0 < ub2i(by) * ub2i(by0), 0 ≤ ub2i(by) * ub2i(by0) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)