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Proof step 11 from proof ubyte-neg (previous step)

b2i(by) < 0 ⊦ fillsgn(8, int2bits(b2i(by))) = [], 2 ^ n→i(# fillsgn(8, int2bits(b2i(by)))) = 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ # bits ≤ n → # fillsgn(n, bits) = n

Rule argument

seq: ⊦ # bits ≤ n → # fillsgn(n, bits) = n subst: [bits, n] → [int2bits(b2i(by)), 8] rotate: F spec: bitopsaux inst: name: fill-length

Additional information

Used simplifier rules: byte-len: ⊦ ¬ 8 < # int2bits(b2i(by));% ⊦ ¬ m ≤ n ↔ n < m; Used terms: int2bits(b2i(by)), 8