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Proof step 4 from proof ubyte-neg (previous step)

b2i(by) < 0 ⊦ bits2int(false ' + fillsgn(8, int2bits(b2i(by)))) = 256 + b2i(by)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
b2i(by) < 0 ⊦ bits2uint(fillsgn(8, int2bits(b2i(by)))) = 256 + b2i(by)

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits2int(false ' + bits) = bits2uint(bits);