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Proof step 1 from proof ubyte-pos-03 (conclusion)

⊦ 0 ≤ i ∧ i < 256 → ub2i(i2b(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 256, 0 ≤ i ⊦ ub2i(i2b(i)) = i

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)