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Proof step 5 from proof ubyte-pos-03 (previous step)

b2i(i2b(i)) < 0, 0 ≤ i, i < 256 ⊦ 256 + b2i(i2b(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 127 < i ∧ i < 256 → b2i(i2b(i)) = i - 256

Rule argument

name: bib-upper rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: byte-in: ⊦ 0 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i;% ⊦ i + (j - i) = j;% ⊦ ¬ i < j ↔ j ≤ i;%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);% ⊦ i = i + j ↔ j = 0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: i