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Proof step 5 from proof ushort-band-shift-01 (previous step)

0 ≤ us2i(sho) ∧ 0 < 8 ∧ 8 < 32 ⊦ band(us2i(sho) / 2 ^ 8, 255) = us2i(sho) / 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 ≤ us2i(sho) ⊦ band(255, us2i(sho) / 256) = us2i(sho) / 256

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)