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Proof step 31 from proof ushort-band-shift (previous step)

1 + j = i * 256 + j0 ∧ j0 ≤ 0 ∧ abs(j0) < 256 ∧ i ≤ 0 ∧ 0 < 256 ∧ 1 + j < 0, s2i(sho) = j * 256, j < 0, ~256 ≤ j ⊦ 255 + j0 = (256 + j) % 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
1 + j = i * 256 + j0, s2i(sho) = j * 256, j < 0, ~256 ≤ j, abs(j0) < 256, j < ~1, j0 ≤ 0, i ≤ 0 ⊦ 255 + j0 = (256 + j) % 256

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;