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Proof step 13 from proof ushort-inj (previous step)

s2i(sho) < 0, 2 ^ 16 + s2i(sho) = us2i(sho0) ⊦ sho = sho0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
s2i(sho) + 65536 = us2i(sho0), s2i(sho) < 0 ⊦ sho = sho0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)