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Proof step 16 from proof ushort-inj (previous step)

¬ s2i(sho0) < 0, s2i(sho) + 65536 = us2i(sho0), s2i(sho) < 0 ⊦ sho = sho0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
s2i(sho) + 65536 = s2i(sho0), 0 ≤ s2i(sho0), s2i(sho) < 0 ⊦ sho = sho0

Rule argument

Additional information

Used simplifier rules: ushort-pos: ⊦ 0 ≤ s2i(sho) → us2i(sho) = s2i(sho);% ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;