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Proof step 19 from proof ushort-inj (previous step)

~32768 ≤ s2i(sho0) ∧ s2i(sho0) ≤ 32767, s2i(sho) + 65536 = s2i(sho0), 0 ≤ s2i(sho0), s2i(sho) < 0 ⊦ sho = sho0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;