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Proof step 5 from proof ushort-inj (previous step)

s2i(sho) = us2i(sho0), 0 ≤ us2i(sho0) ⊦ sho = sho0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ s2i(sho) < 0 → us2i(sho) = 2 ^ 16 + s2i(sho)
Proof step 7:
s2i(sho0) < 0, s2i(sho) = 2 ^ 16 + s2i(sho0), 0 ≤ 2 ^ 16 + s2i(sho0) ⊦ sho = sho0

Rule argument

name: ushort-neg rotate: F subst: [sho] → [sho0]

Additional information

Used simplifier rules: ushort-pos: ⊦ 0 ≤ s2i(sho) → us2i(sho) = s2i(sho);%short-equal: ⊦ s2i(shoi) = s2i(shoj) ↔ shoi = shoj;% ⊦ ¬ i < j ↔ j ≤ i; Used terms: sho0