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Proof step 1 from proof ushort-max-01 (conclusion)

⊦ 65535 ≤ us2i(sho) ↔ us2i(sho) = 65535

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ s2i(sho) < 0 → us2i(sho) = 2 ^ 16 + s2i(sho)

Rule argument

name: ushort-neg rotate: F subst: [sho] → [sho]

Additional information

Used simplifier rules: ushort-max-04: ⊦ ¬ 65535 < us2i(sho);%ushort-pos: ⊦ 0 ≤ s2i(sho) → us2i(sho) = s2i(sho);%short-max-08: ⊦ s2i(sho) ≠ 65535;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ i < 0 → (~1 ≤ i ↔ i = ~1);% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; Used terms: sho