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Proof step 1 from proof ushort-max-02 (conclusion)

⊦ 256 ≤ i ∧ 0 ≤ j → us2i(sho) ≠ i * 256 + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
us2i(sho) = i * 256 + j, 256 ≤ i, 0 < i, 0 ≤ i, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)